5[g+2]=29+3[g-5]

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Solution for 5[g+2]=29+3[g-5] equation:


Simplifying
5[g + 2] = 29 + 3[g + -5]

Reorder the terms:
5[2 + g] = 29 + 3[g + -5]
[2 * 5 + g * 5] = 29 + 3[g + -5]
[10 + 5g] = 29 + 3[g + -5]

Reorder the terms:
10 + 5g = 29 + 3[-5 + g]
10 + 5g = 29 + [-5 * 3 + g * 3]
10 + 5g = 29 + [-15 + 3g]

Combine like terms: 29 + -15 = 14
10 + 5g = 14 + 3g

Solving
10 + 5g = 14 + 3g

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '-3g' to each side of the equation.
10 + 5g + -3g = 14 + 3g + -3g

Combine like terms: 5g + -3g = 2g
10 + 2g = 14 + 3g + -3g

Combine like terms: 3g + -3g = 0
10 + 2g = 14 + 0
10 + 2g = 14

Add '-10' to each side of the equation.
10 + -10 + 2g = 14 + -10

Combine like terms: 10 + -10 = 0
0 + 2g = 14 + -10
2g = 14 + -10

Combine like terms: 14 + -10 = 4
2g = 4

Divide each side by '2'.
g = 2

Simplifying
g = 2

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